Digest for sci.electronics.repair@googlegroups.com - 10 updates in 2 topics

M.Joshi <M.Joshi@eternal-september.org>: Jun 08 08:29AM

Hello all,
 
I am trying to repair the above Samsung laptop which just produces a series
of clicks when you press the power button? I have tried powering up without
the battery and removing any residual capacitor charge by depressing the
power button for 1 minute with neither the battery nor the AC adaptor connected.
 
The battery seems to be charging which indicates that the main 19V input
rail is functional.
 
Looking at the LA-8862P PCB schematic for the laptop, I cannot seem to work
out what the B+ voltage rail is and where it is generated?
 
Also, there is mention of a TPS51125 in the Power Tree block diagram but
it does not appear in any of the circuit schematics later on?
 
Any pointers would be much appreciated.
 
Thanks.
Ken <Ken@invalid.com>: Jun 08 09:38AM -0500

M.Joshi wrote:
> it does not appear in any of the circuit schematics later on?
 
> Any pointers would be much appreciated.
 
> Thanks.
 
You may well have a problem that requires opening up the laptop, but I
would try another power supply before doing that. I have seen many
laptop that fail due to lack of current when under load. In fact I
purchased one for parts that the owner said would not power up, but all
it needed was a power supply. It has been working fine for over two
years now.
"David Farber" <farberbear.unspam@aol.com>: Jun 07 12:04PM -0700

M Philbrook wrote:
> fail in this manner for routers, I replaced my 3 times, now I have a
> transformer 60hz type and works great...
 
> Jamie
 
Hi Jamie,
 
I did replace the faulty cap. As far using a 5 watt zener diode, the
original one is 3mm long and 1.4mm in diameter. That would seem to be in the
under 1 watt category. Also, please see my corrections to my original post.
The zener diode is paralleled by the filter cap, not the power diode.
 
Thanks for your reply.
--
David Farber
Los Osos, CA
John-Del <ohger1s@aol.com>: Jun 07 02:29PM -0700

On Sunday, June 7, 2015 at 11:47:39 AM UTC-4, David Farber wrote:
 
> --
> David Farber
> Los Osos, CA
 
Basic crowbar zener. Meant to protect the device powered by the supply in case the supply runs away.
Jeff Liebermann <jeffl@cruzio.com>: Jun 07 02:37PM -0700

On Sun, 7 Jun 2015 12:04:01 -0700, "David Farber"
 
>The zener diode is paralleled by the filter cap, not the power diode.
 
If the zener is there strictly for protection, the power supply should
work normally without it. Have you tried using it without the zener?
 
If it's in parallel with the output, it's likely some voltage slightly
over 5V, such as 5.6v or 6.8v. If the zener is expected to short upon
overvoltage, I would guess(tm) that a low power zener would be more
appropriate than one that can handle the power.
 
I've had my share of 5v 2A power supplies blow up. I don't recall if
they were made by Jentec, but when I replaced the usual bulging
capacitor(s), most would not recover. I never bothered to
troubleshoot further and just recycled them. Thanks for the hint
about the zener.
 
--
Jeff Liebermann jeffl@cruzio.com
150 Felker St #D http://www.LearnByDestroying.com
Santa Cruz CA 95060 http://802.11junk.com
Skype: JeffLiebermann AE6KS 831-336-2558
"Arfa Daily" <arfa.daily@ntlworld.com>: Jun 08 01:01AM +0100

"John-Del" <ohger1s@aol.com> wrote in message
news:22d3f51e-41b6-4f4c-a893-c2199ff79e6d@googlegroups.com...
>> Los Osos, CA
 
> Basic crowbar zener. Meant to protect the device powered by the supply in
> case the supply runs away.
 
That would be my feeling for the purpose of it, too ...
 
Arfa
"Arfa Daily" <arfa.daily@ntlworld.com>: Jun 08 01:09AM +0100

Also, please see my corrections to my original post.
> The zener diode is paralleled by the filter cap, not the power diode.
 
Although strictly speaking it is correct no matter which way round you say
it, that still comes across sort of wrong, as though the zener has some
primary function, and that of the filter cap is secondary. It would be
better to say that the filter cap is paralleled by the zener, implying that
it's the zener that has the secondary function. Probably just me splitting
hairs though ... :-)
 
Arfa
 
 
"Mark Zacharias" <mark_zacharias@labolgcbs.net>: Jun 07 08:23PM -0500

"Arfa Daily" <arfa.daily@ntlworld.com> wrote in message
news:j35dx.855892$I97.187416@fx31.am4...
>> --
>> David Farber
>> Los Osos, CA
 
1. Cap develops ESR.
2. High frequency AC waveform appears on the desired DC output.
3. Circuit interprets as low DC - attempts to compensate.
4. Actual DC runs away. In the Panasonic example, the 14 volt line would go
to 35 volts.
4. Zener shorts.
5. Ideally this throws off the "Q" of the circuit so much that it simply
stops oscillating. Power supply stops but does not blow up.
 
"Ideally".
 
The old Panasonic switchers still usually fried the primary circuit
switching transistors in this scenario.
 
Remove the shorted zener, replace the cap, observe the voltage at that
point, replace with an appropriate zener.
 
For example, Panasonic put an 18 volt zener across the 14 volt line.
 
If your rated output is 5 volts, maybe a 6 volt zener.
 
Mark Z.
"David Farber" <farberbear.unspam@aol.com>: Jun 07 06:31PM -0700

Arfa Daily wrote:
>> --
>> David Farber
>> Los Osos, CA
 
Hi Arfa,
 
I agree with you regarding the phrasing. Your way does sound better and it
is splitting hairs. (-:
 
I was wondering what would happen if the choke were placed before the
capacitor and zener diode. Wouldn't the choke filter out the spikes and then
make the zener diode unnecessary or at least less likely to short?
 
Thanks for your reply.
--
David Farber
Los Osos, CA
Phil Allison <pallison49@gmail.com>: Jun 07 09:52PM -0700

David Farber wrote:
 

> I was wondering what would happen if the choke were placed before the
> capacitor and zener diode.
 
** A choke would present a high impedance in series with each current pulse from the switching tranny - causing a big drop in the voltage appearing on the electro cap.
 

> Wouldn't the choke filter out the spikes and then
> make the zener diode unnecessary or at least less likely to short?
 
** The zener (probably 6.2 V) conducted heavily and failed short when the electro went high ESR and caused the peak output voltage to go high.
 
An electro that has developed high ESR cannot smooth the current pulses being delivered by the switching tranny and diode, so the output wave has continuous high peaks with a low *average* value. The control loop responds to the low average and tries to correct it by making each current pulse stronger, which only makes things worse.
 
In short, the output electros in a SMPS are critical to it operation and in many cases there in nothing to prevent the output voltage going high when they wear out.
 
I have seen serious damage done to 5V logic when this happens.
 
 
 
... Phil
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