Digest for sci.electronics.repair@googlegroups.com - 2 updates in 1 topic

amdx <amdx@knology.net>: Mar 22 07:18AM -0500

On 3/15/2021 12:58 PM, Peter W. wrote:
> Just that simple, yes. Not sure how much current goes into this device, but you want the diode to be rated at least 2x that current so it does not fail under load.
 
> Peter Wieck
> Melrose Park, PA
 
So your point is, if he has a 1 amp 24V power supply, he needs a 2 amp
24V Zener Diode?
 
Ya, I found one, it is a 1.980 amp 24 Volt Zener at Mouser. Better order
it soon it has a
 
40 week lead time and the price is $802,40.
 
> https://www.mouser.com/ProductDetail/Microchip-Technology/JANTX1N2820B?qs=CP1DtB0LfQcCGfenu8oJbg%3D%3D
 
  In this case, putting a Zener directly across the output of a power
supply output is not the way to do this.
 
As long as you don't require a precise 24 volts, find out what the
current draw is of the square wave generator with your
 
load. Calculate the resistance needed to drop 2 volts. Put the resistor
in series with the Positive output and Zener from the resistor
 
to ground. This way any voltage that is over 24 volts at the Zener will
cause it to conduct and the over voltage will be dissipated in the resistor.
 
  You could also use a 20V Zener and calculate the proper resistor
value so the Zener is actual Zenering all the time and regulating the
voltage,
 
rather than just limiting any over voltages. Adjust resistor value to
not exceed Zener dissipation limits.
 
Mikek
 
 
 
 
 
 
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"Peter W." <peterwieck33@gmail.com>: Mar 22 07:30AM -0700

His goal is to limit the surge at power-up. A diode of the correct rating will do that just fine without a resistor. KISS
 
Peter Wieck
Melrose Park, PA
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